Struvite Remover and Scale Remover Calculation Guide
Easily estimate the amount of Struvite Remover needed for cleaning pipes with our straightforward calculation example. Follow the steps below to determine the chemical requirements for a 1,000 ft section of 6-inch diameter pipe with 1-inch thickness of struvite buildup.
Key Information:
- Pipe Volume:
- 6-inch diameter pipe = 0.196 ft³ per linear foot
- 4-inch diameter pipe (after 1” buildup) = 0.126 ft³ per linear foot
- Struvite Density:
- 1 cubic foot of struvite = 106.08 lbs.
- Chemical Requirement:
- To dissolve 1 lb. of struvite, you'll need 2.0 to 3.0 lbs. of Struvite Remover
- Product Weight:
- 1 gallon of Struvite Remover = 8.63 lbs.
Step-by-Step Calculation:
1. Calculate the volume of struvite buildup per linear foot of a pipe 6” in diameter with 1” thickness:
0.196 ft3 - 0.126 ft3=0.07 ft3 of struvite per linear foot
2. Determine the struvite weight per foot:
0.07 ft3 × 106.08 lbs./ft3=7.43 lbs. of struvite per linear foot
3. Calculate the amount of Struvite Remover needed:
7.43 lbs. × 3 lbs. of remover per lb. of struvite=22.29 lbs. per linear foot
4. Convert pounds to gallons:
22.29 lbs. ÷ 8.63 lbs./gal=2.58 gallons per linear foot
Important Note:
Scale deposits can vary across plants and industries. We recommend conducting product-to-scale ratio testing, as well as testing the scale itself, to ensure accurate treatment.
Need Help with Your Struvite Removal Project?
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